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Chemistry Extension 1
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Published on Nov 18, 2015
Calculations in chemistry and oxidation and reduction
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1.
Chemistry Extension 1
Chemical calculations, oxidation-reduction, investigations
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jules:g
2.
Mole Calculations
n = amount of substance or mols
Remember 1 mol is equal to 6 x 1023 particles
Two formulae you should remember are n = m/M and n = cV
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zenera
3.
Percentage Yield
Percentage yield = actual yield/theoretical yield x 100
As many reactions involve alternative reactions.
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IITA Image Library
4.
Empirical and Molecular Formulae
Divide m by M
Divide all by the smallest n
Determine ratio
If working out the molecular formula then calculate M(empirical formula)
Then divide by M(molecular) and multiply the formula by the simplest ratio
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Malcolm Carlaw
5.
Titration Calculations
Calculate the mols of the known
Calculate the mols of the unknown from the equation
Calculate the concentration of the unknown
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jameskirk.eu
6.
Titration Technique
Clean all gear with distilled water
Rinse the burette and the pipette with the solutions going in them
Check there are no stray drops on the burette or pipette
Don't add too much indicator
Go slowly!!!
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brittgow
7.
Standard Solutions
These are solutions which you make up that you know the exact concentration
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amandabhslater
8.
Mixing Solutions
c1V1 = c2V2
Don't forget to add up all the volume
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EvelynGiggles
9.
Oxidation-Reduction Chemistry
Electrons are transferred from one species to another
One species loses electrons (is oxidised)
One species gains electrons (is reduced)
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jjamv off
10.
Oxidation Numbers
All elements are 0
O is always -2 unless in H2O2 where it is -1
H is always +1 unless in metal hydrides where it is -1
Ions carry their normal charge
Atoms in a polyatomic ion add together to equal the charge on the ion
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Olga Gerrard
11.
Two Step Redox Calculations
These follow the same pattern
But the unknown and known varies as you use both equations
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arbyreed
Miss Hay
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