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Chemistry Extension 1

Published on Nov 18, 2015

Calculations in chemistry and oxidation and reduction

PRESENTATION OUTLINE

Chemistry Extension 1

Chemical calculations, oxidation-reduction, investigations
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Mole Calculations

  • n = amount of substance or mols
  • Remember 1 mol is equal to 6 x 1023 particles
  • Two formulae you should remember are n = m/M and n = cV
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Percentage Yield

  • Percentage yield = actual yield/theoretical yield x 100
  • As many reactions involve alternative reactions.

Empirical and Molecular Formulae

  • Divide m by M
  • Divide all by the smallest n
  • Determine ratio
  • If working out the molecular formula then calculate M(empirical formula)
  • Then divide by M(molecular) and multiply the formula by the simplest ratio

Titration Calculations

  • Calculate the mols of the known
  • Calculate the mols of the unknown from the equation
  • Calculate the concentration of the unknown
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Titration Technique

  • Clean all gear with distilled water
  • Rinse the burette and the pipette with the solutions going in them
  • Check there are no stray drops on the burette or pipette
  • Don't add too much indicator
  • Go slowly!!!
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Standard Solutions

  • These are solutions which you make up that you know the exact concentration

Mixing Solutions

  • c1V1 = c2V2
  • Don't forget to add up all the volume
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Oxidation-Reduction Chemistry

  • Electrons are transferred from one species to another
  • One species loses electrons (is oxidised)
  • One species gains electrons (is reduced)
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Oxidation Numbers

  • All elements are 0
  • O is always -2 unless in H2O2 where it is -1
  • H is always +1 unless in metal hydrides where it is -1
  • Ions carry their normal charge
  • Atoms in a polyatomic ion add together to equal the charge on the ion
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Two Step Redox Calculations

  • These follow the same pattern 
  • But the unknown and known varies as you use both equations
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