M&M'S

SIMPLER PROBABILITY

• There are 102 m&m's in the bag and there are 24 green m&m's. What's the probability of pulling a green?
• 24/102 = 12/51(23.53%)

SIMPLER PROBABILITY (CONT)

• What would be the probability of pulling a brown m&m since there are 9?
• Try it!

ANSWER TO BROWN M&M QUESTION

• 9/102 = 3/34 (8.82%)

HARDER PROBABILITY

• What if we wanted to find the probability of pulling both a green and brown m&m?

HARDER PROBABILITY STEPS

• We know that the probability of drawing a green m&m is 24/102
• And we know that the probability of drawing a brown m&m is 9/102
• Then we use nCr to find our answer (n being the number of different combinations and r being how many are taken out)

HARDER PROBABILITY STEPS (CONT)

• Now we just plug in our numbers!
• Green: 102 nCr 24
• Brown: 102 nCr 9
• Sample space: 102 nCr 33
• Now we add 102 nCr 24 and 102 nCr 9 and divide that result by 102 nCr 33
• And we find that we have about a 2% chance to pull both a green and brown from a bag of m&m's.